leetcode-145-Binary-Tree-Postorder-Traversal

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描述

Given a binary tree, return the postorder traversal of its nodes’ values.

Example:

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Input: [1,null,2,3]
   1
    \
     2
    /
   3

Output: [3,2,1]

Follow up: Recursive solution is trivial, could you do it iteratively?

分析

后序遍历二叉树。

中序遍历二叉树
前序遍历二叉树

解决方案1(Java)

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/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public List<Integer> postorderTraversal(TreeNode root) {
        ArrayList<Integer> result = new ArrayList<Integer>();
        postOrder(root, result);
        return result;
    }
    
    private void postOrder(TreeNode root, ArrayList<Integer> result) {
        if (root == null) {
            return;
        }
        postOrder(root.left, result);
        postOrder(root.right, result);
        result.add(root.val);
    }
}

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