leetcode-179-Largest-Number

描述


Given a list of non negative integers, arrange them such that they form the largest number.

Example 1:

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Input: [10,2]
Output: "210"

Example 2:

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Input: [3,30,34,5,9]
Output: "9534330"

Note: The result may be very large, so you need to return a string instead of an integer.

分析


又是一道自定义排序算法的问题。有两个需要注意的地方,1,虽然这里是按照大小排序,数字更大的排在前面,也要考虑两个数字之间的组合情况,比如下面的测试用例:

Input:[3,30,34,5,9]

Output:”9534303”

Expected:”9534330”

如果只考虑两两的大小比较,”30” > “3”,而真实情况是 “330” > “303”,因此我们应该比较两两组合之后的字符串。

  1. 需要考虑 [0, 0] 这样的 corner case,对于 [0, 0] 如果不做特殊处理,会返回 “00”,而实际上我们只需要 “0”。

解决方案1(Java)


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class Solution {
public String largestNumber(int[] nums) {
if (nums.length == 0) {
return "";
}

String[] nums2Strings = new String[nums.length];

for (int i = 0; i < nums.length; i++) {
nums2Strings[i] = String.valueOf(nums[i]);
}

Arrays.sort(nums2Strings, new Comparator<String>() {
public int compare(String s1, String s2) {
String s1s2 = s1 + s2;
String s2s1 = s2 + s1;
return s2s1.compareTo(s1s2);
}
});

if (nums2Strings[0].equals("0")) {
return "0";
}

StringBuilder result = new StringBuilder();

for (String str: nums2Strings) {
result.append(str);
}
return result.toString();
}
}

题目来源