leetcode-789-Escape-The-Ghosts

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描述

You are playing a simplified Pacman game. You start at the point (0, 0), and your destination is(target[0], target[1]). There are several ghosts on the map, the i-th ghost starts at(ghosts[i][0], ghosts[i][1]).

Each turn, you and all ghosts simultaneously may move in one of 4 cardinal directions: north, east, west, or south, going from the previous point to a new point 1 unit of distance away.

You escape if and only if you can reach the target before any ghost reaches you (for any given moves the ghosts may take.) If you reach any square (including the target) at the same time as a ghost, it doesn’t count as an escape.

Return True if and only if it is possible to escape.

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Example 1:
Input: 
ghosts = [[1, 0], [0, 3]]
target = [0, 1]
Output: true
Explanation: 
You can directly reach the destination (0, 1) at time 1, while the ghosts located at (1, 0) or (0, 3) have no way to catch up with you.
Example 2:
Input: 
ghosts = [[1, 0]]
target = [2, 0]
Output: false
Explanation: 
You need to reach the destination (2, 0), but the ghost at (1, 0) lies between you and the destination.
Example 3:
Input: 
ghosts = [[2, 0]]
target = [1, 0]
Output: false
Explanation: 
The ghost can reach the target at the same time as you.

Note:

  • All points have coordinates with absolute value <= 10000.
  • The number of ghosts will not exceed 100.

分析

题目很长，实际上很简单，计算原点到 target 的距离，与所有 pacman 的距离进行比较，只要有一个 pacman 小于这个距离就返回 false；否则返回 true。

解决方案1(Java)

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class Solution {
    public boolean escapeGhosts(int[][] ghosts, int[] target) {
        int myDist = Math.abs(target[0]) + Math.abs(target[1]);
        for (int[] ghost: ghosts) {
            int distance = Math.abs(ghost[0]-target[0]) + Math.abs(ghost[1]-target[1]);
            if (distance <= myDist) {
                return false;
            }
        }
        return true;
    }
}

题目来源